0=-0.01x^2+0.06x+5.8

Solution for 0=-0.01x^2+0.06x+5.8 equation:

0=-0.01x^2+0.06x+5.8

We move all terms to the left:

0-(-0.01x^2+0.06x+5.8)=0

We add all the numbers together, and all the variables

-(-0.01x^2+0.06x+5.8)=0

We get rid of parentheses

0.01x^2-0.06x-5.8=0

a = 0.01; b = -0.06; c = -5.8;
Δ = b2-4ac
Δ = -0.062-4·0.01·(-5.8)
Δ = 0.2356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.06)-\sqrt{0.2356}}{2*0.01}=\frac{0.06-\sqrt{0.2356}}{0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.06)+\sqrt{0.2356}}{2*0.01}=\frac{0.06+\sqrt{0.2356}}{0.02}
$